Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Mid-Chapter Check Point - Page 541: 19

Answer

$\frac{1}{25}$.

Work Step by Step

The given expression is $=(-125)^{-\frac{2}{3}}$ Factor the radicand. $=((-5)^3)^{-\frac{2}{3}}$ To raise a power to a power, multiply exponents. $=(-5)^{3\cdot(-\frac{2}{3})}$ Simplify. $=(-5)^{-2}$ $=\frac{1}{25}$.
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