Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Mid-Chapter Check Point - Page 541: 12

Answer

$\frac{x^2}{y^4}$.

Work Step by Step

The given expression is $=\sqrt [5]{\frac{x^{10}}{y^{20}}}$ Factor the radicands as a power of $5$. $=\sqrt [5]{\frac{(x^2)^{5}}{(y^4)^{5}}}$ Use power rule. $=\sqrt [5]{\left (\frac{x^2}{y^4}\right )^5}$ Simplify. $=\frac{x^2}{y^4}$.
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