Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.1 - Introduction to Polynomials and Polynomial Functions - Exercise Set - Page 325: 49

Answer

$y^{2n}+2y^n-3$

Work Step by Step

Consider the given polynomial $(7y^{2n}+y^n-4)-(6y^{2n}-y^n-1)$ Need to drop the parentheses. Thus, $(7y^{2n}+y^n-4)-(6y^{2n}-y^n-1)=7y^{2n}+y^n-4-6y^{2n}+y^n+1$ or, $=7y^{2n}-6y^{2n}+y^n+y^n-4+1$ or, $=y^{2n}+2y^n-3$
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