Answer
$-6x^4y^2-3x^2y^2+xy-4x^2y$
Work Step by Step
Consider the given polynomial
$(10x^4y^2-3x^2y^2+2xy)+(-16x^4y^2-4x^2y-xy)$
Need to drop the parentheses.
Thus,
$(10x^4y^2-3x^2y^2+2xy)+(-16x^4y^2-4x^2y-xy)=10x^4y^2-3x^2y^2+2xy-16x^4y^2-4x^2y-xy$
or, $=10x^4y^2-16x^4y^2-3x^2y^2-4x^2y+2xy-xy$
or, $=-6x^4y^2-3x^2y^2+xy-4x^2y$