Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.1 - Introduction to Polynomials and Polynomial Functions - Exercise Set - Page 325: 38

Answer

$-6x^4y^2-3x^2y^2+xy-4x^2y$

Work Step by Step

Consider the given polynomial $(10x^4y^2-3x^2y^2+2xy)+(-16x^4y^2-4x^2y-xy)$ Need to drop the parentheses. Thus, $(10x^4y^2-3x^2y^2+2xy)+(-16x^4y^2-4x^2y-xy)=10x^4y^2-3x^2y^2+2xy-16x^4y^2-4x^2y-xy$ or, $=10x^4y^2-16x^4y^2-3x^2y^2-4x^2y+2xy-xy$ or, $=-6x^4y^2-3x^2y^2+xy-4x^2y$
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