Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.1 - Introduction to Polynomials and Polynomial Functions - Exercise Set - Page 325: 40



Work Step by Step

Consider the given polynomial $(6y^{2n}+y^n+5)+(3y^{2n}-4y^n-15)$ Need to drop the parentheses. Thus, $(6y^{2n}+y^n+5)+(3y^{2n}-4y^n-15)=6y^{2n}+y^n+5+3y^{2n}-4y^n-15$ or, $=6y^{2n}+3y^{2n}+y^n-4y^n+5-15$ or, $=9y^{2n}-3y^n-10$
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