Answer
$x^4y^2+8x^3y+y-6x$
Work Step by Step
Consider the given polynomial
$(3x^4y^2+5x^3y-3y)-(2x^4y^2-3x^3y-4y+6x)$
Need to drop the parentheses and will have to change the sign of each term of the second polynomial because of the presence of the negative outside.
Thus,
$(3x^4y^2+5x^3y-3y)-(2x^4y^2-3x^3y-4y+6x)=3x^4y^2+5x^3y-3y-2x^4y^2+3x^3y+4y-6x$
or, $=3x^4y^2-2x^4y^2+5x^3y+3x^3y-6x+y$
or, $=x^4y^2+8x^3y+y-6x$
