Answer
$6x^2y+19xy+18$
Work Step by Step
Consider the given polynomial
$(8x^2y+12xy+14)+(-2x^2y+7xy+4)$
Need to drop the parentheses.
Thus,
$(8x^2y+12xy+14)+(-2x^2y+7xy+4)=8x^2y+12xy+14-2x^2y+7xy+4$
or, $=8x^2y-2x^2y+12xy+7xy+14+4$
or, $=6x^2y+19xy+18$