Answer
$12x^3+4x^2+12x-14$
Work Step by Step
Consider the given polynomial
$(17x^3-5x^2+4x-3)-(5x^3-9x^2-8x+11)$
Need to drop the parentheses and will have to change the sign of each term of the second polynomial because of the presence of the negative outside.
Thus,
$(17x^3-5x^2+4x-3)-(5x^3-9x^2-8x+11)=17x^3-5x^2+4x-3-5x^3+9x^2+8x-11$
or, $=17x^3-5x^3-5x^2+9x^2+4x+8x-3-11$
or, $=12x^3+4x^2+12x-14$
