Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.1 - Introduction to Polynomials and Polynomial Functions - Exercise Set - Page 325: 32



Work Step by Step

Consider the given polynomial $(\dfrac{1}{5}x^4+\dfrac{1}{3}x^3+\dfrac{3}{8}x^2+6)+(-\dfrac{3}{5}x^4+\dfrac{2}{3}x^3-\dfrac{1}{2}x^2-7)$ Need to drop the parentheses. Thus, $(\dfrac{1}{5}x^4+\dfrac{1}{3}x^3+\dfrac{3}{8}x^2+6)+(-\dfrac{3}{5}x^4+\dfrac{2}{3}x^3-\dfrac{1}{2}x^2-7)=\dfrac{1}{5}x^4+\dfrac{1}{3}x^3+\dfrac{3}{8}x^2+6-\dfrac{3}{5}x^4+\dfrac{2}{3}x^3-\dfrac{1}{2}x^2-7$ $=\dfrac{1}{5}x^4-\dfrac{3}{5}x^4+\dfrac{1}{3}x^3+\dfrac{2}{3}x^3+\dfrac{3}{8}x^2-\dfrac{1}{2}x^2$ $=-\dfrac{2}{5}x^4+x^3-\dfrac{1}{8}x^2$
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