Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set: 31

Answer

$a)-1$ $b)7$ $c)19$ $d)112$

Work Step by Step

$a)f(-2)=3(-2)+5=-1$ $b)f(0)=4(0)+7=7$ $c)f(3)=4(3)+7=19$ $d)f(-100)+f(100)=[3(-100)+5]+[4(100)+7]$ $=[-300+5]+[400+7]$ $=[-295]+[407]$ $=112$
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