Intermediate Algebra for College Students (7th Edition)

a. $h(0) = 5$ b. $h(-1) = 8$ c. $h(4) = 53$ d. $h(-3) = 32$ e. $h(4b) = 48b^{2} + 5$
$$h(x) = 3x^{2} + 5$$ a. $h(0)$ $h(0) = 3(0)^{2} + 5$ $h(0) = 0 + 5$ $h(0) = 5$ b. $h(-1)$ $h(-1) = 3(-1)^{2} + 5$ $h(-1) = 3(1) + 5$ $h(-1) = 3+ 5$ $h(-1) = 8$ c. $h(4)$ $h(4) = 3(4)^{2} + 5$ $h(4) = 3(16) + 5$ $h(4) = 48 + 5$ $h(4) = 53$ d. $h(-3)$ $h(-3) = 3(-3)^{2} + 5$ $h(-3) = 3(9) + 5$ $h(-3) = 27 + 5$ $h(-3) = 32$ e. $h(4b)$ $h(4b) = 3(4b)^{2} + 5$ $h(4b) = 3(16b^{2}) + 5$ $h(4b) = 48b^{2} + 5$