Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set: 14

Answer

$a) -4$ $b) -2$ $c) 46$ $d) 14$ $e) 50b^{2}-4$

Work Step by Step

$a) h(0)= 2(0)^{2}-4=-4$ $b) h(-1)=2(-1)^{2}-4=-2$ $c) h(5)=2(5)^{2}-4=2\times25-4=46$ $d) h(-3)=2(-3)^{2}-4=2\times9-4=14$ $e) h(5b)=2(5b)^{2}-4=2\times25b^{2}-4=50b^{2}-4$
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