Answer
$a) -4$
$b) -2$
$c) 46$
$d) 14$
$e) 50b^{2}-4$
Work Step by Step
$a) h(0)= 2(0)^{2}-4=-4$
$b) h(-1)=2(-1)^{2}-4=-2$
$c) h(5)=2(5)^{2}-4=2\times25-4=46$
$d) h(-3)=2(-3)^{2}-4=2\times9-4=14$
$e) h(5b)=2(5b)^{2}-4=2\times25b^{2}-4=50b^{2}-4$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set - Page 112: 14
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