Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set: 16

Answer

$a) -2$ $b) 37$ $c) 53$ $d)3b^{2}+4b-2$ $e)75a^{2}+20a-2$

Work Step by Step

$a) f(0)=3(0)^{2}+4(0)-2=-2$ $b) f(3)=3(3)^{2}+4(3)-2=27+12-2=37$ $c) f(-5)= 3(-5)^{2}+4(-5)-2=75-20-2=53$ $d) f(b) = 3(b)^{2}+4(b)-2=3b^{2}+4b-2$ $e) f(5a)=3(5a)^{2}+4(5a)-2=75a^{2}+20a-2$
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