Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set: 11

Answer

$a) -2$ $b) -17$ $c) 0$ $d) 12b-2$ $e) 3b+10$

Work Step by Step

$a) g(0)=3\times0-2=-2$ $b) g(-5)=3\times(-5)-2=-17$ $c) g(\frac{2}{3})=3\times\frac{2}{3}-2=2-2=0$ $d) g(4b)=3\times4b-2=12b-2$ $e) g(b+4)=3(b+4)-2=3b+12-2=3b+10$
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