Intermediate Algebra for College Students (7th Edition)

$$\sqrt{f(-1) - f(0)} - [g(2)]^{2} + f(-2) \div g(2) \cdot g(-1) = -38$$
$$\sqrt{f(-1) - f(0)} - [g(2)]^{2} + f(-2) \div g(2) \cdot g(-1)$$ The values of $f(-1), f(0), g(2), f(-2), g(-1)$ can be obtained from the given table. The values in the parentheses indicate the value of $f$ or a given value of $x$ Based on the table: $f(-1) = 3$ $f(0) = -1$ $g(2) = -6$ $f(-2) = 6$ $g(-1) = 4$ Plugging these values to the original equation: $$=\sqrt{3 - (-1)} - [(-6)]^{2} + 6 \div (-6) \cdot 4$$ $$=\sqrt{4} - 36 + 6 \div (-6) \cdot 4$$ $$=2 - 36 + (-1) \cdot 4$$ $$=2 - 36 -4$$ $$=2 - 36 -4$$ $$=- 34 -4$$ $$=- 38$$