Answer
$g(1) = -2$
$f(g(1)) = 10$
Work Step by Step
$f(x) = x^{2} - x + 4$ and $g(x) = 3x - 5$
$g(1) = 3(1) - 5$
$g(1) = 3 - 5$
$g(1) = -2$
$f(g(1)) = (-2)^{2} - (-2) + 4$
$f(g(1)) = 4 +2 + 4$
$f(g(1)) = 10$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set - Page 112: 25
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