Answer
$6820$
Work Step by Step
Here $a_1=-20 $ and $r=-2$; a geometric sequence
$S_n=\dfrac{a_1(1-r^n)}{1-r}$
Thus,
$S_{10}=\dfrac{-20(1-(-2)^{10})}{1-2}=\dfrac{20460}{3}$
or, $=6820$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Mid-Chapter Check Point - Page 858: 9
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