Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Mid-Chapter Check Point - Page 858: 6

Answer

$-13$

Work Step by Step

Here $a_1=\dfrac{3}{2} $ and $d=-\dfrac{1}{2}$ ; an arithmetic sequence $a_n=\dfrac{3}{2} +(n-1)(-\dfrac{1}{2})$ Thus, $a_{30}=\dfrac{3}{2} +(30-1)(-\dfrac{1}{2})=\dfrac{3}{2} -\dfrac{29}{2} $ or, $a_{30}=-13$
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