Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Mid-Chapter Check Point - Page 858: 15

Answer

$\dfrac{5}{11}$

Work Step by Step

The term $0.\overline{45}$ can be written as $0.45+0.0045+...$ Here, $r=0.01$ and $a_1=0.45$; which is an infinite geometric sequence. Their sum is $S_{\infty}=\dfrac{a_1}{1-r}$ Thus, $S_{\infty}=\dfrac{0.45}{1-0.01}$ or, $=\dfrac{45}{99}$ Hence, $=\dfrac{5}{11}$
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