## Intermediate Algebra for College Students (7th Edition)

$3725$
since,we have $\sum_{i=1}^{50}(3i-2)$ Here, terms are: {$1,4,7,10,...,148$}; which is an arithmetic sequence. Their sum is $S_n=\dfrac{n}{2}(a_1+a_n)$ $=\dfrac{50}{2}(1+148)$ or, $=25(149)$ Hence, $=3725$