Answer
$3725$
Work Step by Step
since,we have $\sum_{i=1}^{50}(3i-2)$
Here, terms are: {$1,4,7,10,...,148$}; which is an arithmetic sequence.
Their sum is $S_n=\dfrac{n}{2}(a_1+a_n)$
$=\dfrac{50}{2}(1+148)$
or, $=25(149)$
Hence, $=3725$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Mid-Chapter Check Point - Page 858: 12
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