Answer
$2350$
Work Step by Step
Here $a_1=-2 $ and $d=2$; an arithmetic sequence
$S_n=\dfrac{n}{2}(2a_1+(n-1)d)$
Thus,
$S_{50}=\dfrac{50}{2}(2(-2)+(50-1)2)=25(-4+98)$
or, $=2350$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Mid-Chapter Check Point - Page 858: 8
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