Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Mid-Chapter Check Point - Page 858: 8



Work Step by Step

Here $a_1=-2 $ and $d=2$; an arithmetic sequence $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$ Thus, $S_{50}=\dfrac{50}{2}(2(-2)+(50-1)2)=25(-4+98)$ or, $=2350$
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