Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Mid-Chapter Check Point - Page 858: 4

Answer

$78$

Work Step by Step

Here $a_1=2 $ and $d=4$ $a_n=a_1+(n-1)d=2+(n-1)d$; Thus, $a_{20}=2+(20-1)4=2+(19)(4)$ or, $a_{20}=78$
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