Answer
$1536$
Work Step by Step
Here $a_1=3 $ and $r=2$; a geometric sequence
$a_n=a_1r^{n-1}=3(2)^{n-1}$;
Thus,
$a_{10}=3(2)^{10-1}=3(2)^9$
or, $a_{10}=1536$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Mid-Chapter Check Point - Page 858: 5
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