Answer
$(0,0)$
Work Step by Step
Standard form of a horizontal parabola is $x=a(y-k)^2+h$
Here, vertex:$(h,k)$ and $4a$ is latus rectum.
Since we are given $x=4y^2$
It can be written as:
$x=4(y-0)^2+0$
Thus, vertex: $(0,0)$
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