Answer
Hyperbola
Work Step by Step
Since we are given $4x^2=36+y^2$
It can be written as:
$4x^2-y^2-36=0$
Thus, this shows that the variable $x^2$ and $y^2$ having opposites signs, so the graph of the given equation is a hyperbola.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 10 - Section 10.4 - The Parabola; Identifying Conic Sections - Exercise Set - Page 799: 58
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