## Intermediate Algebra for College Students (7th Edition)

$(0,0)$
Standard form of a horizontal parabola is $x=a(y-k)^2+h$ Here, vertex:$(h,k)$ and $4a$ is latus rectum. Since we are given $x=2y^2$ It can be written as: $x=2(y-0)^2+0$ Thus, vertex: $(0,0)$