Answer
Parabola
Work Step by Step
Standard form of a horizontal parabola is $x=a(y-k)^2+h$
Here, vertex:$(h,k)$ and $4a$ is latus rectum.
Since we are given $x-3-4y=6y^2$
It can be written as:
$-6y^2+x-4y-3=0$
Thus, this shows that only one variable is squared so the graph of the given equation is a parabola.
