## Intermediate Algebra for College Students (7th Edition)

Standard form of a horizontal parabola is $x=a(y-k)^2+h$ Here, vertex:$(h,k)$ and $4a$ is latus rectum. Since we are given $x-7-8y=y^2$ It can be written as: $-y^2+x-8y-7=0$ Thus, this shows that only one variable is squared so the graph of the given equation is a parabola.