Answer
$(-1,-5)$
Work Step by Step
Standard form of a horizontal parabola is $x=a(y-k)^2+h$
Here, vertex:$(h,k)$ and $4a$ is latus rectum.
Since we are given $x=-2(y+5)^2-1$
It can be written as:
$x=-2(y-(-5))^2+(-1)$
Compare the given equation with the standard form.
Thus, vertex: $(-1,-5)$
