## Intermediate Algebra for College Students (7th Edition)

$(-3,3)$
Standard form of a horizontal parabola is $x=a(y-k)^2+h$ Here, vertex:$(h,k)$ and $4a$ is latus rectum. Since we are given $x=y^2-6y+6$ It can be written as: $x=(y^2-6y+9)+6-9$ or, $x=(y-3)^2+(-3)$ Compare the given equation with the standard form. Thus, vertex: $(-3,3)$