## Intermediate Algebra for College Students (7th Edition)

$L=380, B=120$
Let the length of field = L Let the width of field = B 1. $L=B+2$ 2. $2(L+B) = 1000$ $L+B=500$ Put value of L from the first equation to the second equation. $B+260+B=500$ $2B=500-260$ $2B=240$ $B=\frac{240}{2}$ $B=120$ Put value of B in the first equation. $L=120+260$ $=380$