Answer
-4
Work Step by Step
$=\frac{(8-10)^{3}-(-4)^{2}}{2+8(2)\div4}$
$=\frac{(-2)^{3}-16}{2+16\div4}$
$=\frac{-8-16}{2+4}$
$=\frac{-24}{6}$
$=-4$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 1 - Test - Page 101: 17
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