Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Test - Page 101: 17



Work Step by Step

$=\frac{(8-10)^{3}-(-4)^{2}}{2+8(2)\div4}$ $=\frac{(-2)^{3}-16}{2+16\div4}$ $=\frac{-8-16}{2+4}$ $=\frac{-24}{6}$ $=-4$
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