Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Test - Page 101: 20



Work Step by Step

$9x-[10-4(2x-3)]$ $=9x-[10-8x+12]$ $=9x-[22-8x]$ $=9x-22+8x$ $=17x-22$
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