Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Test - Page 101: 19



Work Step by Step

$=5(2y-6)-(4y-3)$ $=5\times2y-5\times6-4y-(-3)$ $=10y-30-4y+3$ $=6y-27$
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