Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Test - Page 101: 15


$$24-36\div 4\cdot 3=-3$$

Work Step by Step

$$24-36\div 4\cdot 3$$ Multiply and divide (left to right): $$36\div 4\cdot 3=27$$ Thus, the equation can be rewritten as: $$24-27$$ $$=-3$$
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