## Intermediate Algebra for College Students (7th Edition)

$\dfrac{1}{4}$
RECALL: $a-b = a+(-b)$ Use the rule above to obtain: $=-\frac{1}{4} + -(-\frac{1}{2}) \\=-\frac{1}{4} + \frac{1}{2}$ Make the fractions similar using their LCD of $4$ to obtain: $=-\frac{1}{4} + \frac{2}{4}$ The addends have opposite signs so subtract their absolute values to obtain: $|\frac{2}{4}| - |-\frac{1}{4}| = \frac{2}{4}-\frac{1}{4} = \frac{1}{4}$ The sum will have the same sign as the number with the bigger absolute value. The positive number has a bigger absolute value so the sum of the two numbers must be positive. Thus, the answer is $\dfrac{1}{4}$.