Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Test: 11

Answer

$\dfrac{1}{4}$

Work Step by Step

RECALL: $a-b = a+(-b)$ Use the rule above to obtain: $=-\frac{1}{4} + -(-\frac{1}{2}) \\=-\frac{1}{4} + \frac{1}{2}$ Make the fractions similar using their LCD of $4$ to obtain: $=-\frac{1}{4} + \frac{2}{4}$ The addends have opposite signs so subtract their absolute values to obtain: $|\frac{2}{4}| - |-\frac{1}{4}| = \frac{2}{4}-\frac{1}{4} = \frac{1}{4}$ The sum will have the same sign as the number with the bigger absolute value. The positive number has a bigger absolute value so the sum of the two numbers must be positive. Thus, the answer is $\dfrac{1}{4}$.
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