Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Test - Page 101: 23



Work Step by Step

$3(2x-4)=9-3(x+1)$ Solve LHS and RHS separately. $6x-12=9-3x-3$ $6x-12=6-3x$ $6x+3x=6+12$ $9x=18$ $x=2$
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