## Intermediate Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 1 - Section 1.7 - Scientific Notation - Exercise Set - Page 89: 50

#### Answer

$1.1 \times 10^{7}$

#### Work Step by Step

Write the numerator and the denominator in scientific notation to obtain: $=\dfrac{(6.6 \times 10^{4}) \times (1 \times 10^{-3})}{(3 \times 10^{-3}) \times (2 \times 10^{-3})}$ Multiply the corresponding parts of the numerator and of the denominator to obtain: $=\dfrac{6.6 \times 10^{4+(-3)}}{6 \times 10^{-3+(-3)}} \\=\dfrac{6.6 \times 10^{1}}{6 \times 10^{-6}}$ Divide the corresponding parts to obtain: $=\dfrac{6.6}{6} \times \dfrac{10^{1}}{10^{-6}} \\=1.1 \times 10^{1-(-6)} \\=1.1 \times 10^{1+6} \\=1.1 \times 10^{7}$

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