Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.7 - Scientific Notation - Exercise Set: 47

Answer

$4 \times 10^{15}$

Work Step by Step

Write the numerator and the denominator in scientific notation to obtain: $=\dfrac{4.8 \times 10^{11}}{1.2 \times 10^{-4}}$ Divide the corresponding parts to obtain: $=\dfrac{4.8}{1.2} \times \dfrac{10^{11}}{10^{-4}} \\=4 \times 10^{11-(-4)} \\=4 \times 10^{11+4} \\=4 \times 10^{15}$
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