## Intermediate Algebra for College Students (7th Edition)

$1.22 \times 10^{-11}$
Multiply the corresponding parts to obtain: $=(6.1 \cdot 2) \times (10^{-8} \cdot 10^{-4}) \\=12.2 \times 10^{(-8)+(-4)} \\=12.2 \times 10^{-12}$ We simplify to put the number in scientific notation. $\\=1.22 \times 10^{-12+1} \\=1.22 \times 10^{-11}$