Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.7 - Scientific Notation - Exercise Set - Page 89: 51



Work Step by Step

$x=\frac{1.2\times10^{9}}{2\times10^{-5}}$ $x=(\frac{1.2}{2})\times(\frac{10^{9}}{10^{-5}})$ $x=0.6\times10^{9-(-5)}=0.6\times10^{14}$ Write 0.6 in scientific notation. $0.6=6\times10^{-1}$ $x=6\times10^{-1}\times10^{14}=6\times10^{13}$
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