Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.7 - Scientific Notation - Exercise Set - Page 89: 48



Work Step by Step

Write the numerator and the denominator in scientific notation to obtain: $$=\frac{2.82\times10^{11}}{1.41×10^{-3}}$$ Divide the corresponding parts to obtain: $$=\frac{2.82}{1.41} \times \frac{10^{11}}{10^{-3}}$$ $$=2\times10^{11-(-3)}$$ $$=2\times10^{14}$$
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