## Intermediate Algebra for College Students (7th Edition)

$$=2\times10^{14}$$
Write the numerator and the denominator in scientific notation to obtain: $$=\frac{2.82\times10^{11}}{1.41×10^{-3}}$$ Divide the corresponding parts to obtain: $$=\frac{2.82}{1.41} \times \frac{10^{11}}{10^{-3}}$$ $$=2\times10^{11-(-3)}$$ $$=2\times10^{14}$$