Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.7 - Scientific Notation - Exercise Set - Page 89: 29


$3.14159 \times 10^0$

Work Step by Step

The number itself is a valid value for $a$, so multiply the number by $10^0$ to obtain: $3.14159 = 3.14159 \times 10^0$
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