Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.7 - Scientific Notation - Exercise Set: 36

Answer

$1.53 \times 10^{-11}$

Work Step by Step

Multiply the corresponding parts to obtain: $=(5.1 \cdot 3) \times (10^{-8} \cdot 10^{-4}) \\=15.3 \times 10^{(-8)+(-4)} \\=15.3 \times 10^{-12}$ We simplify to put the number in scientific notation. $\\=1.53 \times 10^{-12+1} \\=1.53 \times 10^{-11}$
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