Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.1 Rules for Exponents - 3.1 Exercises: 97

Answer

$\frac{11b^{4}}{a^{3}}$

Work Step by Step

$(121a^{-6}b^{8})^{\frac{1}{2}}$ =$(11^{2}\times a^{-6}\times b^{8})^{\frac{1}{2}}$ =$(11^{2})^{\frac{1}{2}}\times(a^{-6})^{\frac{1}{2}}\times(b^{8})^{\frac{1}{2}}$ =$11\times a^{-3}\times b^{4}$ =$11\times \frac{1}{a^{3}}\times b^{4}$ =$\frac{11b^{4}}{a^{3}}$
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