Answer
$\frac{11b^{4}}{a^{3}}$
Work Step by Step
$(121a^{-6}b^{8})^{\frac{1}{2}}$
=$(11^{2}\times a^{-6}\times b^{8})^{\frac{1}{2}}$
=$(11^{2})^{\frac{1}{2}}\times(a^{-6})^{\frac{1}{2}}\times(b^{8})^{\frac{1}{2}}$
=$11\times a^{-3}\times b^{4}$
=$11\times \frac{1}{a^{3}}\times b^{4}$
=$\frac{11b^{4}}{a^{3}}$
