Answer
$2xy^{3}$
Work Step by Step
$(8x^{3}y^{9})^{\frac{1}{3}}$
=$(2^{3}\times x^{3}\times y^{9})^{\frac{1}{3}}$
=$(2^{3})^{\frac{1}{3}}\times(x^{3})^{\frac{1}{3}}\times(y^{9})^{\frac{1}{3}}$
=$2\times x\times y^{3}$
=$2xy^{3}$
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