Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.1 Rules for Exponents - 3.1 Exercises - Page 234: 93



Work Step by Step

$(8x^{3}y^{9})^{\frac{1}{3}}$ =$(2^{3}\times x^{3}\times y^{9})^{\frac{1}{3}}$ =$(2^{3})^{\frac{1}{3}}\times(x^{3})^{\frac{1}{3}}\times(y^{9})^{\frac{1}{3}}$ =$2\times x\times y^{3}$ =$2xy^{3}$
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