Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.1 Rules for Exponents - 3.1 Exercises - Page 234: 95



Work Step by Step

$(64m^{6}n^{12})^{\frac{1}{2}}$ =$(8^{2}\times m^{6}\times n^{12})^{\frac{1}{2}}$ =$(8^{2})^{\frac{1}{2}}\times(m^{6})^{\frac{1}{2}}\times(n^{12})^{\frac{1}{2}}$ =$8\times m^{3}\times n^{6}$ =$8m^{3}n^{6}$
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