Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.1 Rules for Exponents - 3.1 Exercises: 95

Answer

$8m^{3}n^{6}$

Work Step by Step

$(64m^{6}n^{12})^{\frac{1}{2}}$ =$(8^{2}\times m^{6}\times n^{12})^{\frac{1}{2}}$ =$(8^{2})^{\frac{1}{2}}\times(m^{6})^{\frac{1}{2}}\times(n^{12})^{\frac{1}{2}}$ =$8\times m^{3}\times n^{6}$ =$8m^{3}n^{6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.