Answer
$8m^{3}n^{6}$
Work Step by Step
$(64m^{6}n^{12})^{\frac{1}{2}}$
=$(8^{2}\times m^{6}\times n^{12})^{\frac{1}{2}}$
=$(8^{2})^{\frac{1}{2}}\times(m^{6})^{\frac{1}{2}}\times(n^{12})^{\frac{1}{2}}$
=$8\times m^{3}\times n^{6}$
=$8m^{3}n^{6}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 3 - Exponents, Polynomials and Functions - 3.1 Rules for Exponents - 3.1 Exercises - Page 234: 95
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