Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.1 Rules for Exponents - 3.1 Exercises: 96

Answer

$6a^{2}b^{5}$

Work Step by Step

$(1296a^{8}b^{20})^{\frac{1}{4}}$ =$(6^{4}\times a^{8}\times b^{20})^{\frac{1}{4}}$ =$(6^{4})^{\frac{1}{4}}\times(a^{8})^{\frac{1}{4}}\times(b^{20})^{\frac{1}{4}}$ =$6\times a^{2}\times b^{5}$ =$6a^{2}b^{5}$
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