Answer
$3t^{4}u^{3}$
Work Step by Step
$(243t^{20}u^{15})^{\frac{1}{5}}$
=$(3^{5}\times t^{20}\times u^{15})^{\frac{1}{5}}$
=$(3^{5})^{\frac{1}{5}}\times(t^{20})^{\frac{1}{5}}\times(u^{15})^{\frac{1}{5}}$
=$3\times t^{4}\times u^{3}$
=$3t^{4}u^{3}$
