Answer
$\sqrt[3] {n^2mp^2}$
Work Step by Step
Put the denominator of the exponents outside of the radical, and let the numerator become the exponent of each base inside the radical.
$n^\frac{2}{3}m^\frac{1}{3}p^\frac{2}{3}$
$=\sqrt[3] {n^2mp^2}$
